WAEC 2026 Chemistry Practical Questions and Answers is Available Online

WAEC Chemistry Practical free Questions and Answers now released online for Alternative A and B. If you wish to score A1 in Chemistry, this post got you covered. The latest Chemistry Practical specimens Answers for WAEC this year has been taken care of here.

It’s obvious many might be searching for 2026 free West African Examination Council (WAEC) Chemistry Practical expo or runs. Explore all the necessary updates on the Chemistry Practical exams and PDF download below. The Exams schedule from the WAEC Timetable will soon be updated here.

In addition, there is sampled WAEC Chemistry Practical Past Questions and Answers for practice before the main exams. Do well to make good use of the likely WAEC expo/runz Alternative to Chemistry Practical A and B updates provided hereunder.

Table of Contents

Practical Chemistry Answers to Questions

The Practical is divided into two parts:

Quantitative Analysis also known as titration
Qualitative Analysis also known as salt analysis

What is quantitative analysis in chemistry Practical lab?

quantitative chemical analysis, branch of chemistry that deals with the determination of the amount or percentage of one or more constituents of a sample.

format for quantitative analysis is shown below:

What is qualitative analysis in chemistry practical?

Qualitative analysis is a branch of chemistry which deals with identification of elements or grouping of elements present in the sample. The identification of elements is done by undergoing certain test. By observing the response to the test we can identify the elements

Format for qualitative analysis is shown below

Test	Observation	Inference

Practical Apparatus

Bunsen Burner – a gas burner used for heating substances in the laboratory.
Beaker – a cylindrical container with a flat bottom and a lip used for mixing, stirring, and heating liquids
Test Tube – a narrow, cylindrical tube used for mixing and heating small quantities of liquids
Pipette – a thin, graduated tube used to measure and transfer small volumes of liquid.
Graduated Cylinder – a tall, cylindrical container used to measure the volume of liquids.
Balance – an instrument used to measure mass.
Funnel – a conical-shaped tool used to channel liquid or powder into a container with a small opening.
Mortar and Pestle – a tool used for grinding and mixing substances, typically solids.

Others

Toungs
Crucible
Spatula

Past Questions

ALTERNATIVE TO PRACTICAL A

Q1.

A is a solution of KMnO $_{4}$ containing 0.020 moldm $^{- 3}$ . B is a solution of Fe $^{2 +}$ obtained by dissolving 3.8 g of iron granules in 250 cm $^{3}$ of solution.

(a)Put A in the burette. Pipette 20.0 cm $^{3}$ or 25 cm $^{3}$ of B into a conical flask and add 10 cm $^{3}$ of H $_{2}$ SO $_{4}$ . Titrate it with A.

Repeat the titration to obtain concordant titre values. Tabulate your result and calculate the average volume of A used.

MnO $_{4}$ $^{-}$ $_{(a q)}$ + 5Fe $^{2 +}$ $_{(a q)}$ + 8H $^{+}$ $_{(a q)}$ → Mn $^{2 +}$ $_{(a q)}$ + Fe $^{3 +}$ $_{(a q)}$ + 4H $_{2}$ O $_{(l)}$

[ KMnO $_{4}$ = 158.0, Fe = 56.0 ]

(b) From your results and information provided, calculate the:

(i) concentration of B in moldm $^{- 3}$

(ii)concentration of B in gdm $^{- 3}$

(iii) mass of Fe $^{2 +}$ in 250 cm $^{3}$ of B.

(iv) percentage of Fe $^{2 +}$ in the granules.

Answers:

(a) Volume of pipette used (Volume of B used) = 25.0 cm $^{3}$

Burette Readings (cm $^{3}$ )	Rough	1st titre	2nd titre
Final burette readings	18.20	18.50	38.40
Initial burette readings	0.00	0.40	20.20
Volume of A used (KMnO $_{4}$ )	18.20	18.10	18.20

Volume of A used = $\frac{R o u g h + 1 s t t i t r e + 2 n d t i t r e}{3}$

= $\frac{18.20 + 18.10 + 18.20}{3}$

= 18.166

V $_{A}$ = 18.17 cm $^{3}$

(i) Concentration of B in moldm $^{- 3}$

From the balanced equation : MnO $_{4}$ $^{-}$ $_{(a q)}$ + 5Fe $^{2 +}$ $_{(a q)}$ + 8H $^{+}$ $_{(a q)}$ → Mn $^{2 +}$ $_{(a q)}$ + Fe $^{3 +}$ $_{(a q)}$ + 4H $_{2}$ O $_{(l)}$

C $_{A}$ = 0.020 moldm $^{- 3}$ N $_{A}$ = 1

V $_{A}$ = 18.17cm $^{3}$ N $_{B}$ = 5

C $_{B}$ = ?

V $_{B}$ = 25.0cm $^{3}$

Using $\frac{C_{A} V_{A}}{C_{B} V_{B}}$ = $\frac{N_{A}}{N_{B}}$

C $_{B}$ = $\frac{C_{A} V_{A} N_{B}}{N_{A} V_{B}}$

C $_{B}$ = $\frac{0.02 X 18.17 X 5}{25 X 1}$

C $_{B}$ = 0.07268

C $_{B}$ = 0.070 moldm $^{- 3}$

(ii) Concentration of B in gdm $^{- 3}$

If 3.8 g of Fe granules was dissolved in 250 cm $^{3}$ of B

Xg of Fe granules will be dissolved in 1000 cm $^{3}$ of B

X = $\frac{3.8 X 1000}{250}$ = 15.2 gdm $^{- 3}$

Concentration of B in gdm $^{- 3}$ will be 15.2 gdm $^{- 3}$

(iii) Mass of Fe $^{2 +}$ in 250cm $^{3}$ of B.

To get the mass, we’ll use the formula n = $\frac{m a s s}{M o l a r m a s s}$

However, since do not know the number of moles, n , hence we’ll need to obtain n, using n = $\frac{C V}{1000}$ since we have C and V

So, n = $\frac{0.070 \times 250}{1000}$ = 0.025 mole

Now, we can apply n = $\frac{m a s s}{M o l a r m a s s}$ to obtain the mass, given that the Molar mass of Fe was given to be 56

n = $\frac{m a s s}{M o l a r m a s s}$

m = n x M = 0.018 x 56 = 1.02 g

Therefore, 1.02 g of Fe $^{2 +}$ in 250 cm $^{3}$ of B.

(iv) Percentage of Fe $^{2 +}$ in the granules = $\frac{M a s s o f F e^{2 +}}{T o t a l m a s s o f F e g r a n u l e s} \times 100$

= $\frac{1.02}{3.8} \times 100$

= 26.89%

= 26.9%

Q2.(a) Mention two gases that are soluble in water.

(b) Name two apparatus that could be used to measure 9.50 cm $^{3}$ of a solution accurately.

(d) Name three personal protective equipment that are used in the laboratory.

Answers:

(a) Gases that are soluble in water are:

– Ammonia

– Hydrogen chloride

– oxygen,

– carbon dioxide,

– Sulphur dioxide,

– chlorine, and

– hydrogen sulfide.

(b) Apparatus that could be used to measure volume of solutions accurately:

– volumetric flask,

– graduated cylinder,

– burette, or

– volumetric pipette.

(c) In a laboratory, fume cupboards are essential safety equipment used to capture and remove airborne hazardous or poisonous substances like gases, vapours, aerosols, and dust, protecting users from exposure to harmful chemicals.

(d) Personal protective equipment (PPE) used in the laboratory.

– Lab coats

– safety glasses

– respiratory protector

– Hand gloves

– Face shield

Q3.C is a mixture of two simple inorganic salts, one of which is a sodium salt.

Perform the following exercises on C. Record your observation and identify any gas(es) evolved. State the conclusions you draw from the results of each test.

(a) Put all of C into a test tube and add about 10 cm $^{3}$ of distilled water and shake.

b(i) Put about 2 cm $^{3}$ of the filtrate into a boiling tube and heat strongly.

(ii) Put half of the residue into a test tube and add dil. HCl.

(iii) To about 2 cm $^{3}$ of the clear solution from b(ii), add aqueous NaOH in drops, then in excess.

(iv) To another 2 cm $^{3}$ of the clear solution from b(ii), add aqueous ammonia in drops, then in excess.

Answer:

	Test	Observation	Inference
(a)	C + 10cm $^{3}$ of H $_{2}$ O	C partially dissolves	C is a mixture of a soluble and insoluble salt.
b(i)	2cm $^{3}$ of filtrate + heat	Colourless and odourless gas in form of bubbles	CO $_{3}$ $^{2 -}$ suspected
(ii)	residue + t.t + dil. HCl	No visible reaction	NO $_{3}$ $^{-}$ , SO $_{4}$ $^{2 -}$ suspected
(iii)	Solution from b(ii) + NaOH in drops and then in excess	White ppt which is dissolves in excess NaOH	Zn $^{2 +}$ , Pb $^{2 +}$ , Al $^{3 +}$ suspected
(iv)	Solution from b(ii) + NH $_{3}$ in drops and then in excess	White ppt insoluble in excess NH $_{3}$	Pb $^{2 +}$ confirmed.

ALTERNATIVE PRACTICAL B

Q4. D contains 6.30 g of HNO $_{3}$ in 500 cm $_{3}$ of solution. E was prepared by dissolving 8.20 g of washing soda crystals ( Na $_{2}$ CO $_{3}$ .xH $_{2}$ O) in 250 cm $^{3}$ of distilled water.

(a) Put D into the burette and titrate it against 20.0 or 25.0 cm $^{3}$ portion of E using methyl orange as indicator.

Repeat the exercise to obtain concordance titre values.

Tabulate your results and calculate the average volume of the acid used.

(b) Write a balanced chemical equation for the reaction.

(i) calculate the concentration of E in moldm $^{- 3}$ ;

(ii) what is the value of x in Na $_{2}$ CO $_{3}$ .xH $_{2}$ O? [H= 1.0; C =12.0; O = 16.0; Na = 23.0; N = 14.0 ]

Answers:

(a) Volume of pipette used = 25.00 cm $^{3}$

Burette readings (cm $^{3}$ )	Rough	1st titre	2nd titre
Final burette reading	20.90	40.90	21.00
Initial burette reading	0.00	20.10	0.00
Volume of acid, A used	20.90	20.80	21.00

Volume of A used = $\frac{R o u g h + 1 s t t i t r e + 2 n d t i t r e}{3}$

= $\frac{20.90 + 20.80 + 21.00}{3}$

= 20.90 cm $^{3}$

(b) 2HNO $_{3}$ $_{a q}$ + Na $_{2}$ CO $_{3}$ .xH $_{2}$ O $_{a q}$ → 2NaNO $_{3}$ + CO $_{2}$ + (X+1)H $_{2}$ 0(l)

c(i) concentration of E in moldm $^{- 3}$

Since we do not know the concentration of D in moldm $^{- 3}$ , but in g per cm $^{3}$ , it will be difficult using the fomula $\frac{C_{A} V_{A}}{C_{B} V_{B}}$ = $\frac{N_{A}}{N_{B}}$ .

Thus, we must first convert the Conc. of D to moldm $^{- 3}$ .

We were told from the question that D contains 6.30 g of HNO $_{3}$ in 500 cm $_{3}$ ,

So, if D 6.30 g of HNO $_{3}$ was dissolved in 500 cm $_{3}$

then, X g of HNO $_{3}$ will be dissolved in 1000 cm $_{3}$

X = $\frac{6.30 \times 1000}{500}$ = 12.6 gdm $^{- 3}$

Recall that Molar concentration (moldm $^{- 3}$ ) = $\frac{M a s s c o n c e n t r a t i o n (g d m^{- 3})}{M o l a r m a s s}$

Molar mass od HNO $_{3}$ = 1 + 14 + (16 X 3) = 63 g/mol

concentration of D(moldm $^{- 3}$ ) = $\frac{M a s s c o n c e n t r a t i o n (g d m^{- 3})}{M o l a r m a s s}$

C $_{D}$ = $\frac{12.6}{63}$ = 0.20 moldm $^{- 3}$

Now we can use the formula $\frac{C_{D} V_{D}}{C_{E} V_{E}}$ = $\frac{N_{D}}{N_{E}}$ .

Given that

C $_{D}$ = 0.20 moldm $^{- 3}$ N $_{D}$ = 2

V $_{D}$ = 20.90cm $^{3}$ N $_{E}$ = 1

C $_{E}$ = ?

V $_{E}$ = 25.0cm $^{3}$

C $_{B}$ = $\frac{C_{D} V_{D} N_{E}}{N_{D} V_{E}}$

C $_{B}$ = $\frac{0.2 X 20.90 X 1}{25 X 2}$

= 0.0836 moldm $^{- 3}$

= 0.084 moldm $^{- 3}$

(ii) To get the value of x in Na $_{2}$ CO $_{3}$ .xH $_{2}$ O

First, from the question, if 8.20 g of Na $_{2}$ CO $_{3}$ .xH $_{2}$ O was dissolved in 250 cm $^{3}$ of distilled water.

then, Xg of Na $_{2}$ CO $_{3}$ .xH $_{2}$ O will be dissolved in 1000 cm $^{3}$ of distilled water.

So, X = $\frac{8.20 \times 1000}{250}$ = 32.8 gdm $^{- 3}$

Mass concentration of E = 32.8 gdm $^{- 3}$

Recall that concentration of E(moldm $^{- 3}$ ) = $\frac{M a s s c o n c e n t r a t i o n (g d m^{- 3})}{M o l a r m a s s}$

Then, Molar mass of E ( Na $_{2}$ CO $_{3}$ .xH $_{2}$ O ) = $\frac{M a s s c o n c e n t r a t i o n}{M o l a r c o n c e n t r a t i o n}$

= $\frac{32.8}{0.0836}$

= 392.34 g/mol

But Molar mass of Na $_{2}$ CO $_{3}$ .xH $_{2}$ O = Na $_{2}$ CO $_{3}$ + x(H $_{2}$ O)

392.34 = (23 x 2) + 12 + (16 x 3) + 18x

392.34 = 46 + 12 + 48 + 18x

392.34 = 106 + 18x

18x = 392.34 – 106

18x = 286.34

x = $\frac{286.34}{18}$

x = 15.9

x ≈ 16

Q5.(a) An aqueous solution of a salt was added to excess sodium sodium trioxocarbonate (IV) solution in a test tube. There was effervescence, the test tube became warm and a white precipitate was observed. State three inferences that could be drawn from these observations.

(b) Consider the following salts; NH $_{4}$ Cl; PbSO $_{4}$ ; NaHCO $_{3}$ and Cu(NO $_{3}$ ) $_{2}$ .

Select from the list, the salt(s) which:

(i) would not readily dissolve in water;

(ii)produce(s) effervescence with dilute mineral acids;

(iii) decompose(s) on heating;

(iv) dissolve(s) in water to form an alkaline solution;

(v) sublime(s) on heating

(c) A solution of an acid was titrated with sodium hydroxide solution using methylorange as the indicator. State three precautions that are necessary when carrying out such an

Answers:

a(i) Salt solution is acidic

– Reaction is exothermic.

– White precipitate is likely to be a trioxocarbonate(IV) salt of Al, Ca and Zn.

– Prepared solution contained soluble salt of Al, Ca and Zn.

b(i)PbSO $_{4}$

(ii) NaHCO $_{3}$

(iii) NaHCO $_{3}$ ; Cu(NO $_{3}$ ) $_{2}$ .

(iv) NaHCO $_{3}$

(v) NH $_{4}$ Cl

– Wear a lab coat to protect your clothing from spills.

– Ensure to rinse the burette with an acid solution

– Also ensure the funnel is removed immediately after filling the acid into the burette.

– Avoid error due to parallax while taking the reading to determine the end point.

– Ensure all glassware is clean and free of bubbles.

SEE: WAEC Timetable

How to Answer Chemistry Practical WAEC Questions

The following steps are very important for candidates that wish to make good grades:

1. Read all the Instructions provided in the Question paper: This is a very important thing to do as soon as the Question paper is given to you. The essence of this is to help you know what you are required to do. Try as much as possible to adhere to the exams instructions.

2. Fill in Your details where required on the Answer booklets. One of the greatest mistakes candidates make is failure to write their details on the Answers booklet. Filling Your exams details before attempting questions is important because you may forget or may cut off with time.

3. Start with the Questions you know best: This is a smart approach. When you start answering the questions you know very well, you will not only have the confidence to answer the difficult ones but give the marker/examiner a good impression about your knowledge of the subject.

4. Read the Questions at least Thrice before providing solutions: Don not be in a haste to answer questions. Try and read them over and over again to gain full understanding of the questions.

5. Make your handwriting are readable: Take your time to write very well, a good handwriting will make your answers clear understandable.

6. Cross Check your work before submission: I’m all your doing, don’t fail go through your work before submitting your answer booklet. This will enable you to correct mistakes made.

How to pass WAEC exams

It’s important to make your West African Senior Secondary School Certificate Examination a huge success. The following ways are beneficial to candidates that wish to pass WAEC with flying colors:

1. Make adequate Preparation: By preparing very well for the WAEC Chemistry Practical exams, candidates will be able to write the exams confidently.

2. Attending Extra moral Classes: The school teachers might not be able to complete the curriculum on time. On that note, it is advisable for students to attend tutorials that will enlightened the more on the right topics under The syllables.

3. Make good use of Past Questions: The West African Examination Council, WAEC has a pattern of setting questions. Students that make good use of the WAEC Chemistry Practical past Questions and Answers will surely perform well in the exams. Try and practice the questions set on previous years.

4. Use WAEC Chemistry Practical Syllabus: The WAEC Chemistry Practical Syllabus has a list of topics to be treated for years. Candidates should ensures that they use the syllabus while studying and preparing for their exams.

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All we do is to ensure that we provide you with all the necessary steps and updates on how to pass your exams without Stress. Stay tuned for more Related Updates.

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WAEC 2026 Chemistry Practical Questions and Answers is Available Online

Practical Chemistry Answers to Questions

Practical Apparatus

Past Questions

How to Answer Chemistry Practical WAEC Questions

How to pass WAEC exams

WAEC Expo/Runs

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Practical Chemistry Answers to Questions

Practical Apparatus

Past Questions

How to Answer Chemistry Practical WAEC Questions

How to pass WAEC exams

WAEC Expo/Runs

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