WAEC Further Mathematics Questions & Answers Expo 2021/2022 to Objectives/Essay PDF

Free WAEC Further Mathematics Questions and Answers 2021/2022 to Objectives/Essay. Welcome, You are ready to Answer 2021 Further Mathematics questions in WAEC. There are many peoples also online googling Further Mathematics Expo/runs, WAEC 2021 Further maths objectives and theory answers, etc.

 Download WAEC 2021 Further Maths Runz PDF. Further Mathematics WAEC theory and Objectives answer 2021 for paper 1& 2 (OBJ & Theory), WAEC 2021 Further Mathematics essay answers, keep calm and follow everything we have for you concerning these particular Exams.

But before we go into details, WAEC Further Mathematics answers to Questions, there are many secrets concerning The West African Examinations.

WAEC Further Mathematics Answers

WAEC Further Mathematics Exams answers are very common, but how sure are you about the answers? Here we are going to guide you on WAEC 2021 Further Mathematics Answers to questions

Download WAEC Further Mathematics 2021 Objectives Answers PDF

WAEC 2021 Further Mathematics Answers is another section of the exams whereby you will be required to chose the correct options. The options may range from A to D or you may be required to take True or False.

To answer these questions correctly, kindly read the questions at least 3 times. These will help you to pass the WAEC 2020 Further Mathematics questions very well.

Today’s further mathematics objectives questions and answers for WAEC SSCE loading..

WAEC Further Mathematics Theory Answers 2021 ( Expo)

WAEC Further Maths theory Answers also know as Essay answers. This section requires that candidate chose the questions from his or country and answer. The numbers of questions required Will be mentioned in the exam questions paper

EXAMINATION SCHEME

There will be two papers, Papers 1 and 2, both of which must be taken.

PAPER 1: will consist of forty multiple-choice objective questions, covering the entire syllabus. Candidates will be required to answer all questions in 1hours for 40 marks. The questions will be drawn from the sections of the syllabus as follows:

Pure Mathematics – 30 questions
Statistics and probability – 4 questions
Vectors and Mechanics – 6 questions

PAPER 2: will consist of two sections, Sections A and B, to be answered in 2 hours for 100 marks.

Section A will consist of eight compulsory questions that areelementary in type for 48 marks. The questions shall be distributed as follows:

Pure Mathematics – 4 questions
Statistics and Probability – 2 questions
Vectors and Mechanics – 2 questions

Section B will consist of seven questions of greater length and difficulty put into three parts:Parts I, II and III as follows:
Part I: Pure Mathematics – 3 questions
Part II: Statistics and Probability – 2 questions
Part III: Vectors and Mechanics – 2 questions

Candidates will be required to answer four questions with at least one from each part for 52 marks.

WAEC Sample Past Further Maths Answers 

Below are Past Sample Answers

5a)
pr(age)=4/5
pr(fully)=3/4
pr(must)=2/3
pr(age not admitted)=1-4/5
=1/5
pr(fully not admitted)=1-3/4
=1/4
pr(must not admitted)=1-2/3
=1/3
Therefore pr(none admitted)=1/5*1/4*1/3
=1/60
5b)
pr(only age and fully gained admission)=4/5*3/4*1/3
=1/5
================

12a)
tabulate
Marks| 1-10, 11-20, 21-30, 31-40, 41-50,51-60, 61-70, 71-80, 81-90, 91-100
F| 3, 17, 41, 85, 97, 115, 101, 64, 21, 6
C.B| 0.5-105, 10.5-205, 20.5-305, 30.5-405,40.5-505, 50.5-605, 60.5-705, 70.5-805,80.5-905, 90.5-1005
C.F| 0+3=3, 3+17=20, 20+41=61, 61+85=146,146+77=243, 243+115=358, 358+101=459,459+64=523, 523+21=544, 544+6=550
=================

11a)
Given:
f(x)={(4x-x^2)dx
f(x)=2x^2 – x^3/3 + K
f(3)=2(3)^2 – (3)^2/3 + K =21
18 – 9 + K=11
9+K=21
K=21-9
K=12
Therefore
f(x)= -x^3 + 2x^2 + 12
11b)
i) Tn=a+(n-1)d
T2=a+(2-1)d
T2=a+d
T4=a+3d
T8=a+7d
GP
Tn=ar^n-1
T1=ar^1-1
T2=ar^2-1=ar
T3=ar^2
a+d=a …..equation (1)
a+3d=ar …..equation (2)
a+7d=ar^2 …..equation (3)
T3+T5=20
a+2d+a+4d=20
2a+6d=20
a+3d=10 …..equation (4)
…..equation (2)/…..equation (1)
ar/a=a+3d/a+d
r=a+3d/a+d
…..equation (3)/…..equation (2)
ar^2/ar=a+7d/a+3d
r=a+7d/a+3d
but r=r
a+3d/a+d=a+7d/a+3d
(a+3d)^2=(a+d)(a+7d)
a^2+6ad+ad^2
a^2+7ad+ad+7d^2
a^2+8ad+7d^2
a^2+6ad+9d^2=a^2
+8ad+7d^2
6ad+9d^2=8ad+7d^2
6ad-8ad=7d^2-9d^2
-2ad=2d^2
ad=dd
a=d
===================

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