Welcome, 2019 NECO GCE Mathematics Questions and Answers to OBJ/Essay is right here for you. Keep calm and neco reading. We are going to guide you on how to answer NECO GCE mathematics successfully.

2019 NECO GCE Mathematics Questions and Answers to OBJ/Essay – See all the answers and questions on Math for this year’s NECO GCE Maths exams both Objectives and Essay Expo here. Check below for the questions and answers.

You are welcome to your No. one blog that gives you all that you need on Mathematics exam for NECO GCE 2019/2020 NOV/DEC External (private candidates) examination.

This page will give you all that it takes to pass this year NOV/DEC External NECO 2019 GCE Mathematics which according to the timetable will be taken on Saturday, 1st DEC, 2019. In that case, you are required to read through this guide in order to obtain the best EXPO on Math for GCE 2019.

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## NECO GCE Mathematics Answers and Question – Math Expo

But I want to let you know that such thoughts are not correct. You can understand it only if you determine. NECO Math is normally very simple. After this answers that will be given below, we shall also show you the simplest way to pass this subject (Mathematics) both OBJ and Essay.

## Below are Sample Past Questions

b/sin20 = 6/sin30

bsin30 = 6sin120

b 6sin120/sin30

b = 6×0.2511/0.4540

b = 5.7063/0.4540

b = 12.57 ≠ 12.6cm

A = P+ I

where I = 15000*10*3/100=N4500

A=4500+15000 =N19500

A = P+ I

where I = 15000*10*3/100=N4500

A=4500+15000 =N19500

*Question 2——NECO GCE Mathematics Answers and questions*

T=thickness

P=Pages

T*P

T=KP

T=3

P=900

3=900k

k=3/900=1/300

T=P/300

WHERE T=45CM

P=?

45=P/300

P=300*45

P=13500pages

x + y =3______(1)

x² – y² = 15_____(2)

Solution

From equation (2)

x² – y² = 15

(x+y)(x-y) = 15_____(3)

Recall x-y = 3

Substitute the value of (x-y) in equation (3)

3(x + y) = 15

Therefore (x +y) =5

The value of x+y =5

R=7^1/2%

T=3yrs

At the end of year 1

I=PRI/100=300000*15*1/100*2

I=N22500

P=300000+22500+50000

=N372500

I=372500*15*1/200=N27937.50

P=372500+27937.5+50000

=N450437.50

I=450437.50*15*1/200

I=N33782.81

total saving of 3years

=450437.5+33782.81+50000

=N534220.31

n(c)=35

n(b)=26

n(CnB)=x

drawing

40=35-x+x+26-x

40=61-x

x=61-40=21

21 student offer both

U:{all positive <-20 br=””>S:{all even number <14 br=””>T:{all even nus<-20divisible 3=”” br=”” by=””>U={1,2,3,,,20}

S={2,4,6,8,10,12}

T={6,12,18}

SUT={2,4,6,8,10,12,18}

=2rsm^θ/2

=2*4sm^9^4/2

=85m47

=8*0.7314

=5.85cm

draw the diagram

7cm>7cm

area(A)=θper^2/360-1/2r^2 8mθ

=r^2/2{22/180-8mθ}

=49/2[90/180*22/7-8m90]

=49/2{1/2*22/77-1}

=49/2{11/7-1}=44/2{1.57-1}

=49/2{0.57}=13.97cm^2

*NECO GCE 2019 Mathematics answers Loading…Continue to refresh the page for more updates*## How to pass NECO GCE Math Questions

- Study past questions on Mathematics. This is what will help you to pass it very simple
- While studying the past questions, use NECO GCE Syllabus.
- Set time for your study
- Pray to God

## NECO GCE Syllabus

- NUMBER and NUMERATION

- ALGEBRAIC PROCESSES

- MENSURATION

- PLANE GEOMETRY

- TRIGONOMETRY

- STATISTICS AND PROBABILITY

- VECTORS and TRANSFORMATIONS IN A PLANE

- Indices & Sets