# WAEC GCE Mathematics Questions and Answers 2020/2021 OBJ / Essay: Sure Answers

WAEC GCE Mathematics Questions and Answers 2020/2021 to Objectives and Essay is right here.  We are going to give you WAEC GCE Maths Questions that are normally asked and how to attempt WAEC Mathematics Questions in the WAEC GCE Exams.

It is noticed that many candidates are searching for the answers to 2020 WAEC GCE mathematics Questions using different keywords. We shall also share with you a little WAEC GCE 2020 Mathematics Expo as you read on. This Exam, WAEC GCE Mathematics 2020 is controlled, set, and marked by the West African Examination Council. This WAEC Exam is only for Candidates who are currently not in the school system.

In other words, it is for private candidates   WAEC GCE Maths Answers and questions involve questions that will test the candidate’s ability in the Mathematics aspect.

It is so pertinent to understand it and write the correct answers in the exams hall.  WAEC GCE is very important for any candidate who did not clear his or her paper while in school but would have loved to further his or her educational career.

It is the platform set to help this type of candidate to equally have their complete papers and can use it in any institution, hence passing WAEC GCE Mathematics is more than important.

## WAEC GCE Maths Objectives Answers 2020

The objectives section of the exams is normally simple. you will be required to take just an option from multiple choices. Ensures that you go through the question over and over again before making your choice.

PAPER I OBJECTIVES

1. Given that​​ y​​ varies inversely as the square of​​ x.​​ if​​ x=3 when​​ y=100, find the equation connecting ​​ x​​ and​​ y

(a) yx2=300

(b).​​ yx2=900

(c)​​ yx2=100x9100x9​​

(d) y = 900x2 ​​​​

2. Find the value of​​ x for which 32four​​ = 22 base x

(a). three

(b) five

(c) Six

(d) seven

3. Simplify:​​ 2 whole number1/4 x 3 whole number1/2 ÷4 whole number3/8

(a).​​ 5/9

​​ (b)​​ 1 whole number1/5​​

(c)​​ 1 whole number 1/4​​

(d)​​ 1 whole number 4/5

4. There are 250 boys and 150 girls in a school. If 60% of the boys and 40% of the girls play football. What percentage of the school play football?

(a). 40.0%

(b) 42.2%

(c) 50.0%

(d) 52.5%

5. If log10​​ (6 x−4) x-4)​​ – log10​​ 2=1, solve for​​ xx

(a). 2

(b) 3

(c) 4

(d) 5

6. If F =​​ 9C/5+ 32, find C when F = 98.6

(a) 30

(b) 37

(c) 39

(d) 41

7. If​​ y ÷​​ 2 x ​​ = 4 and​​ y−3x=−1, ​​ find the value of (x+y)

(a) 3

(b) 2

(c) 1

(d) -1

8. If​​ x:y:z=2:3:4,​​ Evaluate​​ 9x+3y/6z−2y

(a)1 whole number1/2​​

(b)​​ 2

(c)​​ ​​ 2 whole number1/2​​

(d)​​ 3

9. The volume of a cylindrical tank, 10m high is 385m3. Find the diameter of the tank. Take​​ π=22/7

(a). 14 m

(b). 10 m

(c). 7 m

​​ (d). 5 m

10. The surface of a sphere is​​ 7927cm27927cm2. Find correct to the nearest whole number, its volume. Take​​ ​​ [π=22/7]

(a)113 cm^3

​​ (b)​​ 131cm^3

(c)​​ 311cm^3

(d)​​ 414cm^3

## WAEC GCE Mathematics Essay Questions

Where ever u c
^ it means raise to power
/ division
* multiplication
X normal X =====================

SECTION A ANS ALL
=====================
1a)
(y-1)log4^10= ylog16^10
log4^10 (y-1)= log16^y10
4^(y-1)=16y
4^y-1=4^2y
y-1=2y
-1=2y=y
-1=y
y= -y

1b)
let the actual time for 5km/hr be t
for 4km/hr=30mint + t
4km/hr=0.5 + t
distance = 4(0.5+t)
=2*4t
for 5km/hr, time= t
distance =5t
1+4t=5t
t=2hrs
actual distance = 5*2=10km
==================

2a)
2/3(3x-5)-3/5(2x-3)=3/1
L C M =15
10(3x-5)-9(2x-3)=45
30x-50-18x+27=45
30x-18x=45+50-27
12x-23=45
12x=45+23
12x=68
x=68/12
x=34/6
x=17/3 2b)
U’aS=180-(n+88)
=180-n-88=92-n
also, u’TQ=18m
80degree + 92-n+180-m=180degree
80+92+180-n-m=180degree
352-n-m=180degree
-n-m=180-352
-n-m=-172
+(n+m)= +172
m+n=172dgree
==================

3a)
Tan 23.6° = h/50
Cross multiply
Tan 23.6° x h/50
h = 50 tan 23.6°
= 21.844m‎ 3b)
Area of A = 1/2bh
45 = 1/2 x 10 x h
45 = 5h
h = 9cm
Area of < QTUS = 1/2 ( QT + US)h
= 1/2 ( 6 + 16)9
= 99cm^2
==================

4a)
T6=37
T6=a+(6-1)d
T6=a+5d
a+5d=37 —–(eq1)
s6=147
sn=n/2(2a+(n-1)d)
147=3(2a+5d)
49=2a+5d
2a+5d=49 —-(eq2)
a+5d=37 —(eq1)
2a+5d=49 —(eq2)
a=12 4b)
S15=15/2(2(12)+14d)
S15=15/2(24+14d)
from(1)
a+5d=37
12+5d=37
5d=37-12
5d=25
d=5
S15 = 15/2(24+14(15)
S15= 15/2(24+70)
S15=15/2*94
S15=15*42
S15=630
==================

5a)
draw
U=20
B= y-45
S= y-34
B=bag
S=shoe
let n(B)=y
n(S)=y+11
for bag only y-45
for shoe only y-11-45=y-34 5b)
y-45+45+y-34=120
2y-34=120
2y=154
y=154/2
y=77
number of customers who bought shoe = y+11
77+11=88 5c)
n(bag)=77customers
probability =77/120
=0.642 =====================

SECTION B ANS 5 QUESTIONS ONLY
=====================

10a)
Sin x = 5/13
Using pythagoras rule
M^2 = 13^2 – 5^2 (^ means Raise to power)
M^2 = 169 – 25
M ^2 = 144
M = √144
M = 12
Hence:
Cos x – 2sin x / 2tan x
12/13 – 2(5/13) / 2(5/12)
‎= 12/13 – 10/23 / 5/6
FIND LCM
= 12 – 10/13 / 5/6
= 12/65 10bi)
Considering < LMB
/MB/^2. = 12^2 – 9.6^2
/MB/^2 = 51.84
/MB/ = √51.84
/MB/ = 7.2m
From < AML
/LA/^2 = 2.8^2 + 9.6^2
/LA/ ^2 = 100
/LA/ = √100
/LA/ = 10m 10bii)
Let the angle be. θ
From Tanθ = 9.6/2.8
Tan θ = 3.4288
θ = Tan^-1 ( 3.4288)
= 73.74°
=============

13ai)
given
x(*)y=x+y/2
i)3(*)2/5=3+2/5/2
=(15+2/5)*1/2
=17/5*1/2
=17/10= 1,7/10 13aii)
8(*)y=8^1/4
=8+y/2 =33/4
32+4y=66
4y=66-32
4y=34
y=34/4
y=17/2
y=8^1/2 13b)
given DABC
AB=(^-4/6) and AC =(3/^-8)
so AP =1/2(^-4/6)
AP=(^-2/3)
hence
CP = CA + AP
CP= -(3/^8)+(^-2/3)
CP = (^-5/11)
=================

8a)
In Table Form / Tabular form
X = 1,2,3,4,5
F = m+2, m-1, 2m-3, m+5, 3m-4 = 8m – 1‎
Fx = m+2, 2m-2, 6m-9, 4m+20, 15m-20 = 28m – 9‎
But x̄ ( this symbol (x̄) means X bar)
= 75/23‎
ΣFx / Σf = 75/23 = 28m – 9/8m-1
75/23 = 28m – 9/8m – 1
Cross multiply
75(8m-1) = 23(28m-9)
600m – 75 = 644m – 207
-75 + 207 = 644m – 600m
132 = 44m
M = 3 8bi)
In tabular form
X = 1,2,3,4,5
F = 5,2,3,8,5
Cum Freq= 5,7,10,18,23
Q1 = (N+1/4) = (23+1/4)
= 6
Q3 = (3N + 1/4) = (3*23+1/4)
= 18
Inter quarter range = Q3 – Q1
=. 18-6
= 12 8bii)
Pr. (at least 4 mark)
= 8+3+2+5/23
= 18/23‎
==============

12a)
3y^2-5y+2=0
y^2 – 5/3y + 2/3=0
y^2-5/3y=-2/3
y^2-5/3y+(^-5/6)^2=(-^5/6)^2-2/3
(y-5/6)^2=25/36-2/3
(y-5/6)^2=25/-24/36
(y-5/6)^2=1/36
(y-5/6)=+sqr1/36
y=5/6+1/6
y=5+1/6 or 5-1/6
y=6/6 or 2/3
y=1 or 2/3 12b)
given
M N = [2,3 1,4]
hence
[1,4 2,3] * [m,n x,y] =[2,3 1,4]
[m+2n, x*2y]
[4m+3n, 4x+5y] = [2,3, 1,4]
therefore
m+2n=2——(i)
4m+3n=3——(ii)
from ——(i)
m=2-2n
4(2-2n)+3n=3
8-8n+3n=3
8-5n=3
8-3=5n
5=5n
n=1
hence
m=2-2(1)
M=0
also
x+2y=1——(i)
4x+3y=4——(ii)
from ——(iii)
x=1-2y
4(1-2y)+3y=4
4-8y+3y=4
y=0
therefore x=1-2(0)
x=1
this N=[i i]
================ 11a)
8 students finished
12 tanks in 2/3 (60) mins
= 40 mins
4 student wil finish
X tanks in 1/3 (60)min
= 2omins
X = 4x20x12/8×40
= 3tanks 11b)
L(AB) = 200m |ON| = 12cm
r2 = (AN)2 + (ON )2
r2 = (10)2 +(12)2
r2 = 100 + 144
r2 = 244
r = Sqr 244
r = 15.6CM 11bii)
L(AB) = 2r sin 0/2
20 = 2 (15.6) sin 0/2
20 = 31.2 sin 0/2
sin0/2 = 20/31.2
sin0/2 = 0.6410
0/2 = sin -1 (0.6410)
0/2 = 39.87
0 = 2 (39.87)
0 = 79.74
= 79.7′ (1 d.p ) 11bii)
p 2r + 0/360 x 2TTr
= 2 (15.6 ) + 79.7/360 x 2x 3 x42x15.6
=31.2 + 21.7
= 52.9 cm.

WAEC GCE Mathematics Answers and questions are always the types of questions pertaining to how you can prepare and serve food. It will test your ability to cook and to serve.  WACE Mathematics exams are always very simple and candidates do pass it with flying colors, so you have nothing to worry about as we shall provide you with some tips to use in order to pass this exam.

SEE: WAEC GCE TimeTable

### Simple ways to Pass WAEC GCE Mathematics Questions 2020

As a matter of fact, there are some simple steps you can take in order to pass your Mathematics exam very easily. These are the tips we shall give below so as to guide you in passing this 2020 WAEC Mathematics questions and provide your self with correct answers.

• WAEC 2020 Mathematics syllabus is the very first thing you should think of. If you know the syllabus for Mathematics, then you can easily know which area to concentrate on. So I recommend that you should get this WAEC GCE Syllabus for Mathematics.
• WAEC GCE Past questions on Mathematics should come into your mind. Having the past question for any subject helps you to know the manner and the likes of questions you should expect from that subject so as to be able to answer them accordingly.
• After getting all these items, then the next step is for you to sit down and study this subject (Mathematics) effectively and all the WAEC GCE Mathematics Questions will be very simple for you.
• Lastly, I will recommend that you should have good Mathematics Skills because this is what will be required of you.

#### Pure WAEC GCE Mathematics Answers and expo 2020

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